When sodium chloride reacts with silver nitrate, silver chloride precipitates. What mass of AgCl is produced from 75.0 g AgNO3?
My answer: 63.3g AgCl
right
To find the mass of silver chloride (AgCl) produced in the reaction, you need to use stoichiometry and calculate the number of moles of AgCl formed.
Step 1: Write the balanced chemical equation for the reaction:
NaCl + AgNO3 -> AgCl + NaNO3
According to the equation, one mole of AgNO3 produces one mole of AgCl.
Step 2: Calculate the molar mass of AgNO3 and AgCl:
AgNO3: Ag = 107.87 g/mol, N = 14.01 g/mol, and O = 16.00 g/mol
AgCl: Ag = 107.87 g/mol and Cl = 35.45 g/mol
Step 3: Convert the mass of AgNO3 given (75.0 g) into moles:
moles of AgNO3 = mass / molar mass
moles of AgNO3 = 75.0 g / (107.87 g/mol + 14.01 g/mol + (3 x 16.00 g/mol))
moles of AgNO3 = 75.0 g / 169.88 g/mol
moles of AgNO3 = 0.441 mol
Step 4: Since the stoichiometry is 1:1, the number of moles of AgCl formed is also 0.441 mol.
Step 5: Calculate the mass of AgCl formed:
mass of AgCl = moles of AgCl x molar mass of AgCl
mass of AgCl = 0.441 mol x (107.87 g/mol + 35.45 g/mol)
mass of AgCl = 0.441 mol x 143.32 g/mol
mass of AgCl = 63.3 g
Therefore, the mass of AgCl produced from 75.0 g of AgNO3 is 63.3 grams.
To determine the mass of AgCl produced from 75.0 g AgNO3, we need to consider the balanced chemical equation and the molar mass of AgCl.
The balanced chemical equation for the reaction is:
AgNO3 + NaCl → AgCl + NaNO3
From the equation, we can see that the ratio between AgNO3 and AgCl is 1:1. This means that for every 1 mole of AgNO3 reacted, 1 mole of AgCl is produced.
First, we need to calculate the number of moles of AgNO3 in 75.0 g using its molar mass:
Molar mass of AgNO3 = (1 x atomic mass of Ag) + (1 x atomic mass of N) + (3 x atomic mass of O)
= (1 x 107.87 g/mol) + (1 x 14.01 g/mol) + (3 x 16.00 g/mol)
= 169.87 g/mol
Number of moles of AgNO3 = mass / molar mass
= 75.0 g / 169.87 g/mol
= 0.4416 mol AgNO3
Since the molar ratio between AgNO3 and AgCl is 1:1, the number of moles of AgCl formed is also 0.4416 mol.
Finally, we can calculate the mass of AgCl using its molar mass:
Molar mass of AgCl = (1 x atomic mass of Ag) + (1 x atomic mass of Cl)
= (1 x 107.87 g/mol) + (1 x 35.45 g/mol)
= 143.32 g/mol
Mass of AgCl = number of moles of AgCl x molar mass of AgCl
= 0.4416 mol x 143.32 g/mol
= 63.36 g
So, the mass of AgCl produced from 75.0 g AgNO3 is 63.36 g.