Math

320 + 16x = x^2

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asked by Meg
  1. I will assume we are solving

    x^2 - 16x - 320 = 0

    how about completing the square
    x^2 - 16x + .. = 320 + ...
    x^2 - 16x + 64 = 320+64
    (x-8)^2 = 384
    x-8 = ±√384 = 8√6
    x = 8 ± 8√6

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    posted by Reiny

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