# maths

integrate
-sinx/�ã4+cos^2x dx

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1. integrate
-sinx/�square root 4+cos^2x dx

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posted by Jess 1
2. I assume you mean

sin x/√(4+cos^2 x)

let u = cos x
du = -sin x dx

and you have

-∫1/√(4+u^2) du
standard hyperbolic trig substitution is used to get

-arcsinh(u/2)
= -arcsinh(cosx / 2)

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posted by Steve

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