if height and radius of frustum are h1 nad r1 respectively . if h2 and r2 are the heights and radius of the smaller base of frustum respectively and h2:h1 =1:2,then r2:r1 is equal to?
also 1:2
all linear dimensions of similar figures are in the same ratio.
what does this have to do with surface area?
To find the ratio of r2:r1, we can use the concept of similar triangles. The two frusta are similar because their corresponding sides are proportional.
Let's assume the larger frustum has a height of h1 and a radius of r1, and the smaller frustum has a height of h2 and a radius of r2.
From the given information, we know that h2:h1 = 1:2. This means that the height of the smaller frustum is half the height of the larger frustum.
Since the frusta are similar, we can conclude that the ratio of their corresponding sides (base radii) is the same as the ratio of their corresponding heights. Therefore:
r2:r1 = h2:h1
Substituting the given values h2:h1 = 1:2, we get:
r2:r1 = 1:2
So, the ratio of r2:r1 is 1:2.