What is the z-score for a test score of 440 in which the test has a normal distribution of N(400, 50)?
Z = (score-mean)/SD
mean-score/sd
Equation needs to be "score-mean" rather than the opposite, so scores above the mean will have a positive Z score and those below the mean will have a negative Z score.
To calculate the z-score for a given test score in a normal distribution, you need to use the formula:
z = (x - μ) / σ
where:
- z is the z-score
- x is the test score
- μ is the mean of the distribution
- σ is the standard deviation of the distribution
In this case, for a test score of 440 with a normal distribution of N(400, 50), you can substitute the values into the formula to find the z-score.
z = (440 - 400) / 50
z = 40 / 50
z = 0.8
Therefore, the z-score for a test score of 440 in a normal distribution N(400, 50) is 0.8.