The overall length of a piccolo is 30.6 cm. The resonating air column vibrates as in a pipe that is open at both ends. Assume the speed of sound is 343 m/s. (a) Find the frequency of the lowest note a piccolo can play, assuming the speed of sound in air is 343 m/s. (b) Opening holes in the side effectively shortens the length of the resonant column. If the highest note a piccolo can sound is 41.0 kHz, find the distance between adjacent antinodes for this mode of vibration. Assume the speed of sound is 343 m/s
f(n) = nv/2L
The lowest frequency is
f1=v/2L =343/2•0.306=560 Hz.
Distance between adjacent antinodes is λ/2 and λ=v/f
So λ2=v/2f=343/2•41000 =0.0042 m