Is the period of f(x) = 2cos(3x - ð) 2ð/3?
ð = pi
one period is from x = 0 to x = 2 pi/3
so that the argument of the trig function changes by 2 pi
so the answer is 2 pi/3
To determine the period of the function f(x) = 2cos(3x - ð), we need to remember the general form of a cosine function: f(x) = A*cos(Bx - C) + D.
In this particular example, we have f(x) = 2cos(3x - ð). Comparing this to the general form, we can identify A = 2, B = 3, C = ð, and D = 0.
The period of a cosine function is given by the formula T = (2ð) / |B|. Therefore, in this case, the period T can be calculated as T = (2ð) / |3| = 2ð/3.
So, yes, the period of f(x) = 2cos(3x - ð) is indeed 2ð/3.