Tell whether the lines for each pair of equations are parallel, perpendicular, or neither.
x + 5y = –20
y = –7/8x – 1 and
32x – 28y = –36
parallel
perpendicular
neither
I think its neither?
Is it perpendicular? opposite reciprocals
Determine if the graphs of the equations are parallel, perpendicular, or neither:
4x – 3y = 6
6x + 8y = 9
To determine whether the lines are parallel, perpendicular, or neither, we need to compare the slopes of the two equations.
1) For the first pair of equations:
Equation 1: x + 5y = –20 (let's rearrange it in slope-intercept form)
5y = -x - 20
y = -(1/5)x - 4
The slope of Equation 1 is -1/5.
Equation 2: y = -7/8x - 1
The slope of Equation 2 is -7/8.
Since the slopes (-1/5 and -7/8) are not equal and not negative reciprocals, the lines represented by these equations are neither parallel nor perpendicular.
2) For the second pair of equations:
Equation 1: y = -7/8x - 1 (no need to rearrange)
The slope of Equation 1 is -7/8.
Equation 2: 32x - 28y = -36 (let's rearrange it in slope-intercept form)
-28y = -32x - 36
y = (8/7)x + 9/7
The slope of Equation 2 is 8/7.
Since the slopes (-7/8 and 8/7) are not equal and not negative reciprocals, the lines represented by these equations are neither parallel nor perpendicular.
Therefore, the correct answer is neither.
slope of first line = -1/5
slope of 2nd line = -7/8
slope of 3rd line = +32/28 = -8/7
mmmh, so using what you learned about slopes , what do you think?
Hint: you are wrong.