What critical t value would be needed to construct a 90% confidence interval on a sample of size 22?
1.717
1.323
2.080
1.321
1.721
Looking it up in the back of a statistics text in a table for "distribution of t probability," you need to realize that 1 - .9 = .1.
Try .1 with n-1 or 21 df.
2.080
To determine the critical t value needed to construct a 90% confidence interval, we can use the t-distribution table or a statistical software. The critical t value is based on the confidence level (90%) and the degrees of freedom, which is equal to the sample size minus 1 (22 - 1 = 21 in this case).
Looking up the critical t value for a 90% confidence level with 21 degrees of freedom, we find that the closest value is 1.721. Therefore, the correct answer is 1.721.