A rotating wheel requires 4.17 s to rotate
through 37 rev. Its angular speed at the end
of the 4.17 s interval is 104 rad/s.
What is its constant angular acceleration?
Assume the angular acceleration has the same
sign as the angular velocity.
bingo was his namo
A car is moving from Rest.After 10sec it's wheel rotate 360times in 1min.If the radius of the wheel is 50cm. Then find angular acceleration and angular velocity after 30s
To find the constant angular acceleration, we can use the formula:
ω_f = ω_i + αt
Where:
ω_f = final angular velocity
ω_i = initial angular velocity
α = angular acceleration
t = time interval
In this case, we are given:
ω_f = 104 rad/s (angular speed at the end of the 4.17s interval)
ω_i = 0 rad/s (initial angular velocity, as the wheel starts from rest)
t = 4.17 s
Now, let's plug these values into the formula and solve for α:
104 rad/s = 0 rad/s + α * 4.17 s
Subtracting 0 rad/s from both sides:
104 rad/s = α * 4.17 s
Dividing both sides by 4.17 s:
α = 104 rad/s / 4.17 s
Calculating:
α ≈ 24.94 rad/s^2
Therefore, the constant angular acceleration of the rotating wheel is approximately 24.94 rad/s^2.