math

how would you solve [(*square root*125)^4]^1/6

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  1. The "square root" of a number simply means the number is raised to the power of 1/2 or 0.5.

    So your question becomes (((125)^1/2)^4)^1/6

    When you have exponents beside each other you simply multiply them.

    So the question becomes 125^(0.5*4*1/6)

    = 125^(1/3)

    Now what number multiplied by itself 3 times gives you 125?

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    posted by Dan
  2. 5^3 = 125, but now what do i do?

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    posted by Cynthia
  3. 5^3 = 125

    So how do we get 125^(1/3) from this?

    Simply take the cubed root of both sides.

    (5^3)^(1/3) = 125(^1/3)

    What then, must the cubed root of 125 be?

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    posted by Dan
  4. five. got it now thanks so much

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    posted by Cynthia
  5. No problem :)

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    posted by Dan

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