Calculate the mass of baking soda, NaHCO3, needed to neutralize 3.0mL of 3.0 M hydrochloric acid.
1. Write the equation.
2. Convert what you have to mols. L x M = mols.
3. Convert mols of what you have from step 2 (mols HCl) to mols of what yu want, in this case it is NaHCO3.
4. Convert mols NaHCO3 to grams NaHCO3.
mols x molar mass = grams.
Post your work if you get stuck.
i need help getting the equation? i missed a couple of days and im so lost
yea i cant get the equation either and i was there
Equation.
NaHCO3 + HCl ==> NaCl + H2O + CO2
simple, huh?
Don't forget to change mL HCl to L since the mol equation is M x L = mols.
what's the answer?
Show me your steps. I don't need the practice.
Wait, I'm confused. Why do you need the equation?
yall are idots!!!!
To calculate the mass of baking soda (NaHCO3) needed to neutralize a given volume and concentration of hydrochloric acid (HCl), we can follow these steps:
Step 1: Determine the balanced chemical equation for the neutralization reaction between HCl and NaHCO3. The equation is as follows:
HCl + NaHCO3 -> NaCl + H2O + CO2
From the balanced equation, we can see that 1 mole of HCl reacts with 1 mole of NaHCO3.
Step 2: Convert the given volume of HCl solution to moles. Since the concentration of HCl is given as 3.0 M and the volume is 3.0 mL, we can use the formula:
moles of HCl = concentration × volume (in liters)
Since the volume is given in milliliters, we need to convert it to liters by dividing by 1000. Thus:
volume (in liters) = 3.0 mL ÷ 1000 = 0.003 L
moles of HCl = 3.0 M × 0.003 L = 0.009 moles
Step 3: Since the balanced equation shows a 1:1 mole ratio between HCl and NaHCO3, the moles of NaHCO3 needed to neutralize the HCl are also 0.009 moles.
Step 4: Finally, we can calculate the mass of NaHCO3 using its molar mass, which is the sum of the atomic masses of its constituent elements:
Na (sodium) = 22.99 g/mol
H (hydrogen) = 1.01 g/mol
C (carbon) = 12.01 g/mol
O (oxygen) = 16.00 g/mol
Molar mass of NaHCO3 = (22.99 + 1.01 + 12.01 + (16.00 × 3)) g/mol = 84.01 g/mol
mass of NaHCO3 = moles of NaHCO3 × molar mass of NaHCO3
mass of NaHCO3 = 0.009 moles × 84.01 g/mol
Therefore, the mass of baking soda (NaHCO3) needed to neutralize 3.0 mL of 3.0 M hydrochloric acid is approximately 0.756 g.