x-(12-x)=38 please explain
d+3(d-4)=20 please explain
x-(12-x)=38
x + x - 12 = 38
Add 12 to both sides of the equation.
2x = 50
x = 25
d+3(d-4)=20
d + 3d - 12 = 20
4d = 32
d = ?
on the 1st problem i don't understand how x is being added when the sign is subtraction
Two negatives make a positive.
To solve the equation x - (12 - x) = 38, you need to simplify the expression on the left side and then isolate the variable x.
Step 1: Distribute the negative sign to the terms inside the parentheses:
x - 12 + x = 38
Step 2: Combine like terms on the left side:
2x - 12 = 38
Step 3: Add 12 to both sides of the equation to isolate the variable on one side:
2x = 38 + 12
2x = 50
Step 4: Divide both sides of the equation by 2 to solve for x:
2x/2 = 50/2
x = 25
Therefore, the solution to the equation x - (12 - x) = 38 is x = 25.