At what DISTANCE from the earth's surface will a mass of 5.0kg be just 45.0N in weight
"g"=45/5=8m/s^2
but g varies inversley with distance squared.
8/9.8=(re/(H+re))^2
solve for h
but g varies inversley with distance squared.
8/9.8=(re/(H+re))^2
solve for h