Physics

In the absence of air resistance, a projectile is launched from and returns to ground level. It follows a trajectory similar to that in the figure below and has a range of 15 m. Suppose the launch speed is doubled, and the projectile is fired at the same angle above the ground. What is the new range?

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  1. range will be proportional to speed,and time in air.

    so how does speed affect time in air?

    consider time in air...
    hf=h0 + vosinTheta*time-1/2 g t^2

    0=0+ t(V-1/2 g t)
    so t=2V/g so time in air is directly proportinal to initial speed.

    range is then proportional to v^2
    so if it was 15m, it is now 15*4 since speed was doubled

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    bobpursley

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