The engine of a 1250 kg car provides a forward directed force of 3,560 N. If the car accelerates at a rate of 2.60 m/s2, what is the total resistive force (wind resistance, friction, etc.) acting on the car?

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  1. With zero resistive force, the acceleration would be
    a = F/M = 2.848 m/s^2

    Since it is only accelerating at 2.60 m/s^2, the resistive force is:

    F - Fbackward = M a
    Fbackward = F - M a
    = 3560 - 2.60 M

    Fbackward = 310 N

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