Chemistry

when 10.0 ml of a .20 M Cu (NO3)2 solution is mixed with 15.0 mL of 0.20M NaOH, what is the theoretical yield (grams) of copper (II) hydroxide?

asked by Lily
  1. Write and balance the equation.
    Convert Cu(NO3)2 to mols. mol = M x L = ?
    Using the coefficients in the balanced equation convert mols Cu(NO3)2 to mols Cu(OH)2.
    Now convert mols Cu(OH)2 to grams. g = mols x molar mass. This is the theoretical yield.

    posted by DrBob222
  2. what's the balanced equation?

    posted by Lily
  3. Cu(NO3)2 + 2NaOH ==> Cu(OH)2 + 2HNO3

    posted by DrBob222

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