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In a trapezium ABCD,ABperpendicular DC.if angle A=4x degree,angle B=(6x+10degree),angle C=(3x10degree) & angle D=5x degree.find each angle of trapezium.
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trapezium ABCD, with AB and DC being parallel, with diagonal connecting A and C, angle ABC is 86, angle ADC is y, angle dac is 66 and angle bac is x, no angle given for bcd or bca or acd. find x and y, So I said that BCD is 94
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ABCD is a cyclic trapezium whose sides AD and BC are parallel to each other .If angle ABC = 72 degree then what is the measure of the angle BCD .
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ABCD is a quadrilateral in which AB parallel DC and AD=BC.prove that (1)angle A + angle C=180 degree= angle + angle D (2)AC=BD
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ABCD is a quadrilateral in which AB parallel DC and AD=BC.prove that (1)angle A + angle C =180 degree = angle B + angle D (2)AC=BD
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is my answer correct, please? thanks very much M = measurement If M angle 1 = 60 degrees, then m angle 3 + m angle 5 = what is answer? i put 90 degree for angle 3 which is right angle + 60 degrees = 150 given: m angle 1 = m angle
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in a triangle the sum of the angle is 180degrees. if angle A is three times angle B and Angle C is 10 degrees more than twice Angle A. Find the measures of the three anges to the newarest degree
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