The initial speed of a body is 2.14 m/s.
What is its speed after 1.87 s if it accelerates uniformly at 4.31 m/s^2?
Answer in units of m/s
Well, I must say, this body seems to be in a hurry! Let's calculate its speed after 1.87 seconds with a "speedy" acceleration of 4.31 meters per second squared.
To find the final speed, we can use the equation:
v = u + at
Where:
v = final speed
u = initial speed
a = acceleration
t = time
Plugging in the given values, we have:
v = 2.14 m/s + (4.31 m/s²)(1.87 s)
Calculating that out gives us:
v ≈ 2.14 m/s + (8.0597 m/s)(1.87 s)
v ≈ 2.14 m/s + 15.0783 m
v ≈ 17.2183 m/s
So, after 1.87 seconds, the body will be zooming along at approximately 17.22 meters per second. Now, that's quite the speed demon!