A buffet-style restaurant has 18 tables that seat 23 people each. A church group of 401 has rented the restaurant for a banquet. If the pastor of another church, his wife, and their nine children come as invited guests, what is the least number of people can sit at any one table?- Please help Ms.Sue and Writeacher.
401 + 11 = 412
412 / 18 = 22.9
Oh Ms.Sue! That almost look like the story problem that was an example in the previous page in my math book! I should follow that. Thank you very much Ms.Sue!
Sorry for that Ms.Sue. But seriously thank you!
You're very welcome. Losa. :-)
What is your answer?
To find the least number of people that can sit at any one table, we need to divide the total number of people attending the banquet by the number of tables available.
In this case, the total number of people attending is 401 from the church group, plus 1 pastor, 1 wife, and 9 children from another church. So the total number of people is 401 + 1 + 1 + 9 = 412.
Now, we need to divide this number by the number of tables available. The restaurant has 18 tables that seat 23 people each. So to find the least number of people that can sit at any one table, we divide 412 by 18.
412 ÷ 18 = 22.89
Since we cannot have a fraction of a person, we need to round up to the next whole number to ensure that each table has enough seats. So the least number of people that can sit at any one table is 23.
Therefore, at least 23 people can sit at any one table in the buffet-style restaurant.