Some object moves 220.0 m at an angle of 42° north of west. During this motion, a 68.0 N force acts on the same object, doing +5460.0 J of work on the object. Assuming the force is applied horizontal to ground, what is this force’s orientation? Is there more than one possible answer? Explain.

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  1. W=F•d•cosθ,
    cosθ =W/F•d =
    θ =arccos 0.65=68.6º
    The force is applied at 68.6º with
    the displacement or
    with 360 º -68.6 with the displacement

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