# calculus

In the early 1960s, radioactive strontium-90 was released during atmospheric testing of nuclear weapons and got into the bones of people alive at the time. If the half-life of strontium-90 is 27 years, what fraction of the strontium-90 absorbed in 1962 remained in people's bones in 1994?

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1. 1994-1962 = 32 years

A = Ao*2^-t/27, so
A/Ao = 2^-32/27 = .4397 = 43.97%

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2. 1994-1962 = 32 years

(.5)^(1/27)=.974654

.5 because half life

.974654^32

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