a wire 4m long carrying current of 5A place at right angle to B of 6web/m2 the force experience by the wire in SI unit is A LONG SPRING IS STRETCHED BY 2Cm and P.E stored in it is U if the string is stretched by 10 cm then the P.E stored would be
1.
F=I•B•L=5•6•4=120 N
2.
U=k•x1²/2.
k=2•U/x1²
pe=k•x2²/2 =2•U•x2²/2•x1²=U•x2²/x1²=
=U(10/2)²=25U.