A pencil box and a notebook together cost $6.28. The notebook costs
$0.70 more than the pencil box. How much does the notebook cost?
A) $4.19
B) $2.09
C) $3.49
D) $2.79
Let's assume the cost of the pencil box is x dollars.
According to the given information, the notebook costs $0.70 more than the pencil box. Therefore, the cost of the notebook is (x + $0.70).
Now, we can set up an equation to solve for x:
Cost of pencil box + Cost of notebook = $6.28
x + (x + $0.70) = $6.28
2x + $0.70 = $6.28
Subtracting $0.70 from both sides:
2x = $6.28 - $0.70
2x = $5.58
Dividing both sides by 2:
x = $5.58 / 2
x = $2.79
Therefore, the cost of the pencil box is $2.79.
Since the notebook costs $0.70 more, its cost is:
$2.79 + $0.70 = $3.49
So, the notebook costs $3.49.
Therefore, the correct option is C) $3.49.
Let's solve this problem step by step.
Let's assume the cost of the pencil box is x dollars.
According to the given information, the cost of the notebook is $0.70 more than the cost of the pencil box, which means it costs (x + $0.70).
Now, we know that the total cost of the pencil box and the notebook together is $6.28. So we can write the equation:
x + (x + $0.70) = $6.28
Simplifying this equation, we get:
2x + $0.70 = $6.28
Subtracting $0.70 from both sides:
2x = $6.28 - $0.70
2x = $5.58
Dividing both sides by 2:
x = $2.79
Therefore, the cost of the pencil box is $2.79.
Now, to find the cost of the notebook, we can substitute the value of x back into the equation:
Notebook cost = x + $0.70
Notebook cost = $2.79 + $0.70
Notebook cost = $3.49
Therefore, the correct answer is C) $3.49.
Let x = the pencil box. Solve for x.
x + x + 0.70 = 6.28