Physics(please check)


Solve for Q

Q= sin^-1 1.5/9.8

I got 8.80 Is this correct?

I have a TI-30 calculator and to do the sin^-1 I pushed the 2nd button and then sin. I am not sure if this is correct.

asked by Hannah
  1. If that is 11.5 in the numerator, no way. Sine cannot be over 1.0 ever. So arcsin-greater than one is nuts.

    posted by bobpursley
  2. No it is sin^-1 (1.15/9.8)

    posted by Hannah
  3. This is arcsin(1.15/9.8)=
    =arcsin 0.117=6.74 degr

    posted by Elena

Respond to this Question

First Name

Your Response

Similar Questions

  1. Trigonometry

    Solve the equation for solutions in the interval 0<=theta<2pi Problem 1. 3cot^2-4csc=1 My attempt: 3(cos^2/sin^2)-4/sin=1 3(cos^2/sin^2) - 4sin/sin^2 = 1 3cos^2 -4sin =sin^2 3cos^2-(1-cos^2) =4sin 4cos^2 -1 =4sin Cos^2 -
  2. math

    Can anyone help w/ these. 1) Solve the equation in the internal [0deg, 360deg]. a) sin 2x = -sin x b) sin 2T = -1/2 (where T is angle) c) 4 sin^2T = 3 2) Evaluate the expression. sin(arctan 2) 3) Rewrite the following w/o using
  3. Trig

    4. Asked to simplify the expression sin(180−è), Rory volunteered the following solution: sin(180−è) = sin 180−sin è, and, because sin 180 is zero, it follows that sin(180−è) is the same as −sin
  4. Math

    Asked to simplify the expression sin(180−è), Rory volunteered the following solution: sin(180−è) = sin 180−sin è, and, because sin 180 is zero, it follows that
  5. TRIG!

    Posted by hayden on Monday, February 23, 2009 at 4:05pm. sin^6 x + cos^6 x=1 - (3/4)sin^2 2x work on one side only! Responses Trig please help! - Reiny, Monday, February 23, 2009 at 4:27pm LS looks like the sum of cubes sin^6 x +
  6. Trigonometry (Help and Check)

    Evaluate (exact answers): a) sin^-1(cos30) Need help. What do I do? b) sin[(cos^-1((sqrt2)/(2)))+[(sin^-1((sqrt2)/(2)))] = sin(45+45) = sin90 = 1 Is this correct? c) cos(arctan5/7) = 7/(sqrt74) = (7sqrt74)/74 Is this correct?
  7. Math(Please help)

    1)tan Q = -3/4 Find cosQ -3^2 + 4^2 = x^2 9+16 = sqrt 25 = 5 cos = ad/hy = -4/5 Am I correct? 2) Use the sum and difference identites sin[x + pi/4] + sin[x-pi/4] = -1 sinx cospi/4 + cosxsin pi/4 + sinx cos pi/4 - cosx sin pi/4 =
  8. Math (Integrals) (Using given method)

    I would like to solve the ∫sin^2(pix) dx Using the given substitution identity: sin^2(x) = (1/2)(1-cos2x) This is what I did so far: ∫sin^2(pix) let u = pix du = pi dx (1/pi)∫sin^2(u)du Applying the identity is where I'm
  9. Calculus

    I need to find the exact solutions on the interval [0,2pi) for: 2sin^2(x/2) - 3sin(x/2) + 1 = 0 I would start: (2sin(x/2)-1)(sin(x/2)-1) = 0 sin(x/2)=1/2 and sin(x/2)=1 what's next? Ok, what angle has a sin equal to say 1/2 sin
  10. Calculus - MathMate Please help

    ok, i tried to do what you told me but i cant solve it for c because they cancel each others out! the integral for the first one i got is [sin(c)cos(x)-cos(c)sin(x)+sin(x)+c] and the integral for the 2nd one i got is

More Similar Questions