While heating two different samples of water at sea level, one boils at 102°C and one boils at 99.2°C. Calculate the percent error for each sample from the theoretical 100.0°C.
[(102-100)/100]*100 = ?
[(99.2-100.0)/100]*100 =
2%
.8
To calculate the percent error for each sample, we can use the formula:
Percent Error = [(Measured Value - Theoretical Value) / Theoretical Value] * 100
For the first sample:
Measured Value = 102°C
Theoretical Value = 100.0°C
Percent Error = [(102 - 100.0) / 100.0] * 100
Percent Error = [2.0 / 100.0] * 100
Percent Error = 2.0%
For the second sample:
Measured Value = 99.2°C
Theoretical Value = 100.0°C
Percent Error = [(99.2 - 100.0) / 100.0] * 100
Percent Error = [-0.8 / 100.0] * 100
Percent Error = -0.8%
So, the percent error for the first sample is 2.0% and for the second sample is -0.8%.
To calculate the percent error for each sample, we need to compare the measured values (boiling points) with the theoretical value (100.0°C). The percent error formula is given by:
Percent Error = [(|Measured Value - Theoretical Value|) / Theoretical Value] * 100
Let's calculate the percent error for each sample:
Sample 1:
Measured Value = 102°C
Theoretical Value = 100.0°C
Percent Error = [(|102 - 100.0|) / 100.0] * 100
= [2.0 / 100.0] * 100
= 2.0%
So, the percent error for sample 1 is 2.0%.
Sample 2:
Measured Value = 99.2°C
Theoretical Value = 100.0°C
Percent Error = [(|99.2 - 100.0|) / 100.0] * 100
= [0.8 / 100.0] * 100
= 0.8%
Therefore, the percent error for sample 2 is 0.8%.