How many molecules of (CH3)2NH are needed to react completely with 2.00mg of H2C2O4? Help i don't understand this process!
I worked this last night for you. I can look for it if you can't find it.
http://www.jiskha.com/display.cgi?id=1340075278
To determine the number of molecules of (CH3)2NH needed to react completely with 2.00mg of H2C2O4, we need to follow a series of steps. Here's a step-by-step process to solve this problem:
Step 1: Write the balanced chemical equation:
First, we need the balanced chemical equation for the reaction between (CH3)2NH and H2C2O4. Let's assume it is:
2(CH3)2NH + H2C2O4 → 2(CH3)2NHC2O4H + H2O
Step 2: Determine the molar mass:
Next, calculate the molar mass of H2C2O4. Hydrogen (H) has a molar mass of 1 g/mol, carbon (C) has a molar mass of 12 g/mol, and oxygen (O) has a molar mass of 16 g/mol. Since there are two carbon atoms and four oxygen atoms in the compound, the molar mass of H2C2O4 is:
2(1.01 g/mol) + 2(12.01 g/mol) + 4(16.00 g/mol) = 90.04 g/mol
Step 3: Convert mass to moles:
Now we need to convert the given mass of H2C2O4 to moles. We can use the formula:
moles = mass / molar mass
In this case,
moles of H2C2O4 = 2.00 mg / 90.04 g/mol
Step 4: Use stoichiometry:
To determine the ratio between (CH3)2NH and H2C2O4, we need to refer to the balanced chemical equation. From the equation, we can see that it takes 2 moles of (CH3)2NH to react with 1 mole of H2C2O4.
Step 5: Calculate the number of moles of (CH3)2NH:
Using the mole ratio from step 4, we can find the number of moles of (CH3)2NH needed to react completely with the given amount of H2C2O4.
moles of (CH3)2NH = (moles of H2C2O4) × (2 moles of (CH3)2NH / 1 mole of H2C2O4)
Step 6: Convert moles to molecules:
Lastly, convert the moles of (CH3)2NH to the number of molecules. To do this, we multiply the number of moles by Avogadro's number, which is approximately 6.022 × 10^23 molecules/mol.
number of molecules of (CH3)2NH = (moles of (CH3)2NH) × (6.022 × 10^23 molecules/mol)
By following these steps, you can calculate the number of molecules of (CH3)2NH needed to react completely with 2.00mg of H2C2O4.