what volume of methane is needed to completely react with 500 liters of oxygen?
Well, I hope you're ready for a gas-tastic answer! To figure out the volume of methane needed to react with 500 liters of oxygen, we need to consider the balanced equation for the combustion of methane.
CH4 + 2O2 → CO2 + 2H2O
According to the equation, we need 1 mole of methane (CH4) to react with 2 moles of oxygen (O2).
Now, grab your imaginary lab coat and goggles, because we have some stoichiometry to do! The molar volume at standard temperature and pressure (STP) is about 22.4 liters.
So, to calculate the volume of methane needed, we'll have to compare the molar ratio between methane and oxygen. For every 2 moles of oxygen, we need 1 mole of methane.
If we have 500 liters of oxygen, we can calculate the number of moles using the molar volume at STP:
500 liters of O2 / 22.4 liters (mol⁻¹) ≈ 22.32 moles of O2
Since we need 1 mole of CH4 for every 2 moles of O2, we'll need half that amount of methane:
22.32 moles of O2 / 2 = 11.16 moles of CH4
Now, let's convert moles back to liters using the molar volume at STP:
11.16 moles of CH4 * 22.4 liters (mol⁻¹) ≈ 250.46 liters of CH4
So, it looks like you'll need approximately 250.46 liters of methane to completely react with 500 liters of oxygen. That's a lot of gas! Just remember, it's all fun and games until someone lights a match. Safety first, my friend!
To determine the volume of methane needed to completely react with 500 liters of oxygen, we first need to balance the chemical equation for the combustion of methane (CH4) with oxygen (O2) to form carbon dioxide (CO2) and water vapor (H2O).
The balanced equation is:
CH4 + 2O2 → CO2 + 2H2O
From the balanced equation, we can see that one molecule of methane reacts with two molecules of oxygen.
To find the volume of methane needed, we need to know the volume ratio between methane and oxygen. From the balanced equation, we can see that the ratio of methane to oxygen is 1:2.
Since we have 500 liters of oxygen, we can calculate the volume of methane needed using the ratio:
Volume of methane = (Volume of oxygen) / (Ratio of methane to oxygen)
Volume of methane = 500 liters / 2
Volume of methane = 250 liters
Therefore, 250 liters of methane is needed to completely react with 500 liters of oxygen.
To determine the volume of methane needed to completely react with oxygen, we need to determine the stoichiometry of the balanced chemical equation for the reaction between methane (CH4) and oxygen (O2).
The balanced chemical equation for the combustion of methane is as follows:
CH4 + 2O2 -> CO2 + 2H2O
From the balanced equation, we can see that 1 mole of methane reacts with 2 moles of oxygen to produce 1 mole of carbon dioxide and 2 moles of water.
We know that the volume of a gas at constant temperature and pressure is directly proportional to the number of moles of that gas. Therefore, if we know the volume of one gas involved in a reaction, we can determine the volume of another gas involved in the same reaction using the mole ratio from the balanced chemical equation.
In this case, to determine the volume of methane needed to react with 500 liters of oxygen, we need to set up a conversion using the ratio of the coefficients from the balanced equation.
1 mole of CH4 → 2 moles of O2
1 mole of CH4 will react with 2 moles of O2. Since we already know the volume of O2 (500 liters), we can use the ratio as follows:
(500 liters of O2) x (1 mole of CH4 / 2 moles of O2) = volume of CH4
Now we need the molar volume of a gas at standard temperature and pressure (STP), which is 22.4 liters per mole. We can use this value to convert the volume of CH4 from moles to liters:
(volume of CH4) x (22.4 liters per mole) = volume of CH4 in liters
By following these steps and performing the necessary calculations, you can determine the volume of methane needed to completely react with 500 liters of oxygen.
1. Write the equation and balance it.
CH4 + 2O2 ==> CO2 + 2H2O
2. You need not convert to moles if all of the components of a reaction are gases; i.e., the volumes are proportional to the coefficients in the equation.
Therefore, 500 L O2 x (1 mole CH4/2 moles O2) = 500 L x (1/2) = ??