If you want to produce 2.00 kg of ethylene glycol from the reaction of C2H4Cl2 and Na2CO3, what is the minimum amount of C2H4Cl2 that is needed? C2H4Cl2(l) + Na2CO3(s) + H2O(l)C2H6O2(l) + 2NaCl(aq) + CO2(g)
Well, if you want to produce 2.00 kg of ethylene glycol, you better have a lot of C2H4Cl2! But don't worry, I'll do the math for you.
First, we need to find the molar mass of ethylene glycol (C2H6O2). Let me grab my clown calculator... *beep beep beep* Ah, it's approximately 62.07 g/mol.
Now, we need to find the number of moles in 2.00 kg of ethylene glycol. Let me do some more clown math... 2.00 kg is the same as 2000 g. So, dividing by the molar mass, we get approximately 32.2 moles.
According to the balanced equation, we know that 1 mole of C2H4Cl2 reacts with 1 mole of ethylene glycol. So, we need at least 32.2 moles of C2H4Cl2 to produce 2.00 kg of ethylene glycol.
I hope you have a clown-sized container of C2H4Cl2 ready for this chemical reaction! Good luck!
To find the minimum amount of C2H4Cl2 needed to produce 2.00 kg of ethylene glycol (C2H6O2), we need to calculate the stoichiometric ratio between C2H4Cl2 and C2H6O2.
The balanced equation for the reaction is:
C2H4Cl2(l) + Na2CO3(s) + H2O(l) → C2H6O2(l) + 2NaCl(aq) + CO2(g)
According to the balanced equation, for every 1 mole of C2H4Cl2, we obtain 1 mole of C2H6O2. We can use this information to calculate the number of moles of C2H4Cl2 needed to produce 2.00 kg of C2H6O2.
First, let's convert the mass of C2H6O2 to moles.
The molar mass of C2H6O2 = 2 * atomic mass(C) + 6 * atomic mass(H) + 2 * atomic mass(O)
= 2 * 12.01 g/mol + 6 * 1.01 g/mol + 2 * 16.00 g/mol
= 62.07 g/mol
Number of moles of C2H6O2 = mass of C2H6O2 / molar mass of C2H6O2
= 2000 g / 62.07 g/mol
= 32.22 mol
Since the stoichiometric ratio between C2H4Cl2 and C2H6O2 is 1:1, we will need 32.22 moles of C2H4Cl2 to produce 32.22 moles of C2H6O2.
Finally, let's convert the moles of C2H4Cl2 to grams to identify the minimum amount of C2H4Cl2 needed.
The molar mass of C2H4Cl2 = 2 * atomic mass(C) + 4 * atomic mass(H) + 2 * atomic mass(Cl)
= 2 * 12.01 g/mol + 4 * 1.01 g/mol + 2 * 35.45 g/mol
= 98.96 g/mol
Mass of C2H4Cl2 = number of moles of C2H4Cl2 * molar mass of C2H4Cl2
= 32.22 mol * 98.96 g/mol
= 3,187.63 g
Therefore, the minimum amount of C2H4Cl2 needed to produce 2.00 kg of C2H6O2 is approximately 3,187.6 grams.
To find the minimum amount of C2H4Cl2 needed to produce 2.00 kg of ethylene glycol (C2H6O2), we need to determine the stoichiometry of the reaction and then calculate the molar masses.
First, let's balance the chemical equation:
C2H4Cl2(l) + Na2CO3(s) + H2O(l) → C2H6O2(l) + 2NaCl(aq) + CO2(g)
The balanced equation shows that for every mole of C2H4Cl2, we produce one mole of C2H6O2.
Next, we need to calculate the molar mass of C2H6O2 using the periodic table:
C = 12.01 g/mol
H = 1.01 g/mol
O = 16.00 g/mol
C2H6O2:
2(12.01 g/mol) + 6(1.01 g/mol) + 2(16.00 g/mol) = 62.07 g/mol
The molar mass of C2H6O2 is 62.07 g/mol.
Now we can set up the calculation:
(2.00 kg)/(62.07 g/mol) = 32.24 mol
To produce 32.24 moles of C2H6O2, we need an equal amount of moles of C2H4Cl2. Therefore, the minimum amount of C2H4Cl2 needed is 32.24 moles.
Convert 2 kg to grams = 2000 g and to mols. mols = grams/molar mass.
Using the coefficients in the balanced equation, convert mols ethylene glycol to mols C2H4Cl2.
Convert mols C2H4Cl2 to grams. g = mols x molar mass.