# calculus (check my work please)

Not sure if it is right, I have check with the answer in the book and a few integral calculators but they seem to get a different answer

∫ sec^3(x)tan^3(x) dx
∫ sec^3(x)tan(x)(sec^2(x)-1) dx
∫ tan(x)sec(x)[sec^4(x)-sec^2(x)] dx
∫ tan(x)sec(x)[(tan^2(x)+1)^2-tan^2(x)-1] dx
∫ tan(x)sec(x)(1+2tan(x)+tan^2(x)-tan^2(x)-1) dx
∫ 2tan^2(x)sec(x) dx
∫ 2(sec^2(x)-1)sec(x) dx
∫ 2sec^3(x)-2sec(x) dx
2∫ sec^3(x) dx -2∫ sec(x) dx
*reduction formula
2tan(x)sec(x)-ln(tan(x)+sec(x))

1. 0
wolfram alpha

When you see lis of results click on:

Wolfram Alpha:Computational Knowledge Engine

When page be open in rectangle type:

integrate sec^3(x)tan^3(x) dx

and click option =

After few secons you will see result.

Then click option Show steps

posted by Bosnian
2. I did, I got a completely different result. Also, SAY SOMETHING USEFUL NEXT TIME!!! tired of you spamming that stupid reply

posted by Jay

posted by Bosnian
4. right, because my answer can be simplified into:

sec^5(x)/5-sec^3(x)/3

posted by Jay

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