Mathematics

(in this question they did not give me any diagrams)
use pie 22/7
(a) a piece of wire is bent to form a square of area 121cm squared

Calculate the length of each side of the square.
Calculate the perimeter of the square.

(b) the same piece of wire was bent to form a circle.

Calculate the radius of the circle.
Calculate the area of the circle.

PLEASE EXPLAIN HOW YOU GOT EACH ANSWER THANK YOU.

asked by INDIANA
  1. first, it's "pi" not "pie"
    121 = 11^2, so the wire is bent into an 11×11 square. 4 sides of 11cm = 44cm perimeter.

    for a circle, the circumference is 2πr, and the area is πr^2. We have 122cm of wire, so c = 121. r = 121/2π = 19.26cm

    the area of the circle is πr^2 = π(c/2π)^2 = c^2/4π = 121^2/4π = 1165cm^2

    posted by Steve
  2. How did you get 122cm of wire??

    posted by INDIANA
  3. Come on, Indiana!

    Could you not see that Steve made a simple typing error??
    He did use the correct number of 121 in the very next line, so clearly no harm was done.

    Both his answers are correct.

    posted by Reiny
  4. A piece of wire is bent to form a square of area 121cm.
    Calculate:

    a)the length of each side of the square

    b)the perimeter of the square

    The piece of wire is now bent to form a circle using π=3.14

    Calculate:
    a)The radius of the circle

    posted by Baller T
  5. area of the square = 121cm²
    s² = 121
    s = square root of 121
    s = 11 cm
    the length of each side of the square is 11cm.
    perimeter of the square = 4s
    = 4*11
    = 44 cm
    length of the wire = c of circle
    121 cm = 2πr
    121 cm = 2*22/7* r
    r = 121 by 2 * 22/7
    r = 19.26 cm
    therefore,
    area of the circle = πr²
    = 22/7 * 19.26 * 19.26
    = 1165 cm²

    thank you!!

    posted by fathima raffi

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