What is the balanced equation for the neutralization of lactic acid using Sodium bicarbonate?
HC3H5O2 + NaHCO3 ==> H2O + CO2 + NaC3HO2
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The balanced equation for the neutralization of lactic acid, C3H6O3, with sodium bicarbonate, NaHCO3, can be written as:
C3H6O3 + NaHCO3 -> C3H5NaO3 + H2O + CO2
In this reaction, lactic acid reacts with sodium bicarbonate to form sodium lactate, water, and carbon dioxide.
To determine the balanced equation for the neutralization of lactic acid using sodium bicarbonate, we first need to know the chemical formulas of both compounds.
The chemical formula for lactic acid is C₃H₆O₃, and the formula for sodium bicarbonate is NaHCO₃.
Now, let's write the equation and balance it step by step:
Step 1: Write the chemical equation for the reaction.
C₃H₆O₃ + NaHCO₃ →
Step 2: Identify the elements present on each side of the equation.
On the left side, we have carbon (C), hydrogen (H), and oxygen (O). On the right side, we have sodium (Na), hydrogen (H), carbon (C), and oxygen (O).
Step 3: Balance the carbon atoms.
Since there is one carbon atom in lactic acid and one in sodium bicarbonate, they are already balanced.
Step 4: Balance the hydrogen atoms.
There are six hydrogen atoms in lactic acid and only one in sodium bicarbonate. To balance hydrogen, we need to put a coefficient of six (6) in front of sodium bicarbonate.
C₃H₆O₃ + 6NaHCO₃ →
Step 5: Balance the oxygen atoms.
There are three oxygen atoms in lactic acid and three in sodium bicarbonate. So, the oxygen atoms are already balanced.
Step 6: Balance the sodium atoms.
To balance sodium, we need to put a coefficient of three (3) in front of sodium bicarbonate.
C₃H₆O₃ + 3NaHCO₃ →
Finally, the balanced equation for the neutralization of lactic acid using sodium bicarbonate is:
C₃H₆O₃ + 3NaHCO₃ → 3H₂O + 3CO₂ + Na₃C₃H₅O₃
Please note that the coefficients in front of the formulas represent the stoichiometric coefficients, indicating the ratios of reactants and products in the balanced equation.