solve equation.
2p^2-50=0
PLEASE HELP
2p^2-50=0
2p^2=50
p^2=25
p squared equals fifty, so to get p by itself you must take the square root of each side.
p = plus or minus 5
*p squared equals twentyfive, so...
To solve the quadratic equation 2p^2 - 50 = 0, we can use the quadratic formula or factoring.
Method 1: Quadratic Formula
The quadratic formula is given by:
p = (-b ± √(b^2 - 4ac)) / (2a)
In this equation, a = 2, b = 0, and c = -50.
Substituting these values into the formula, we get:
p = (-(0) ± √((0)^2 - 4(2)(-50))) / (2(2))
p = (± √(0 - (-400))) / 4
p = (± √(400)) / 4
p = ± 20 / 4
p = ± 5
Therefore, the solutions to the equation 2p^2 - 50 = 0 are p = 5 and p = -5.
Method 2: Factoring
First, let's rewrite the equation in factored form:
2p^2 - 50 = 2(p^2 - 25)
Next, we can rewrite the expression inside the parentheses as a difference of squares:
2p^2 - 50 = 2(p - 5)(p + 5)
Setting each factor to zero, we get:
p - 5 = 0 -> p = 5
p + 5 = 0 -> p = -5
Again, the solutions to the equation are p = 5 and p = -5.