{Y= 3x
Y-x=4
So far I have done this. Please tell me the next steps. Thank you.
X=Y-4
Y=3(4-Y)
Y=12-3Y
from
x = y-4 , sub in y=3x
x = 3x - 4
x - 3x= -4
-2x = -4
divide both sides by -2
x = 2
sub into y=3x
y = 3(2) = 6
x = 2, y = 6
your second last line
Y=3(4-Y)
should have said:
Y = 3(y-4)
then
y = 3y - 12
-2y = -12
y = 6, just like I had mine
y = 3 x
y - x = 4
3 x - x = 4
2x = 4 Divide both sides by 2
x = 4 / 2 = 2
y = 3 x
y = 3 * 2 = 6
To find the solution to the given system of equations, you can substitute the expression for Y in the first equation into the second equation. Here's how you can proceed:
1. Replace Y in the second equation with its expression from the first equation:
Y = 3x
The second equation becomes:
3x - x = 4
2. Simplify the equation by combining like terms on the left side:
2x = 4
3. Divide both sides of the equation by 2:
x = 2
Now that you have found the value of x, you can substitute it back into one of the original equations to solve for Y. Let's use the first equation:
Y = 3x
Y = 3(2)
Y = 6
So, the solution to the system of equations is x = 2 and y = 6.