Can't figure this out, HELP!:
What is the velocity (v) of a stream with a discharge (Q) of 8.53 x 10^3 m 3/s and a cross-sectional area (A) of 5.27 x 10^3 m2?
To find the velocity (v) of the stream, you would use the formula v = Q/A, where Q is the discharge and A is the cross-sectional area.
In this case, the given discharge Q is 8.53 x 10^3 m^3/s, and the given cross-sectional area A is 5.27 x 10^3 m^2.
To find the velocity (v), simply divide the discharge by the cross-sectional area using the given formula:
v = Q / A
Plugging in the given values:
v = (8.53 x 10^3 m^3/s) / (5.27 x 10^3 m^2)
Now, simplify the equation by dividing the numbers:
v = 1.62 m/s
Therefore, the velocity (v) of the stream is 1.62 m/s.