# Calculus

Find the derivative

1. y = e^xSin²x
2. y = (x³+1)e^-4
3. y = x²e^Sinx

1. if y= uv

y'= u v' + v u'

int the first, u=e^x v=sin^2x
du= e^x dx dv=2sinxcosx dx

y= e^x *2sinx cosx + e^x sin^2x

I will be happy to critique your thinking on the others.

posted by bobpursley

posted by Anonymous
3. Oh but thank you.

posted by Anonymous
4. Ok, I wrote number 2 wrong. Number 1 and number 3 equations are correct but number 2 is actually y = (x²+1)e^-4

1) y = e^x(Sin²x)
2) y = (x²+1)e^-4
3) y = x²(e^Sinx)

posted by Anonymous

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