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Suppose the amount of heat removed when 3.0kg of water freezes at 0 degree C were removed from ethyl alcohol and its freezing/melting point of -114 degree C. How many kilograms of ethyl alcohol would freeze?

PLEASE GIVE ME SOME HINTS!!!THANKS A LOT!!!!

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  1. Look up the heat of fusion of ethanol.

    Heat in water freezing= masswater*Hfwater

    Heat in alchol freezing=massalcohol*Hfalc

    set the equal, and solve for mass of alcohol.

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    bobpursley
  2. Am i Correct The correct answer is 9.3 kg ?

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  3. (m_(water ) 〖Lf〗_water)/〖Lf〗_alcohol =m_alcohol
    (3.0×(33.5×〖10〗^4 ))/((10.8×〖10〗^4 ) )=m_alcohol=9.3kg

    Maryo you are right! :)

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  4. i guess the correct answer is 9.3 kg. but i don't know how to get this answer?

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