Sonia counts the faces on a cube. Then, she connects a cube and counts the faces that she can see on the two cubes . How many faces will be visible if she ends up with a row of 5 cubes?
4 faces for each cube in the middle, and 5 faces for the ones on the ends.
So, for n cubes n>2,
4(n-2) + 5(2) = 4n + 2
I don't get it. Can you help me again. I need more details
OK, like i said idk.stands 4 (i don't know)!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
To determine the number of faces that will be visible when Sonia ends up with a row of 5 cubes, we need to consider how the cubes are connected.
Each cube has 6 faces, but when cubes are connected, some faces become hidden as they are no longer visible from the outside.
When we connect two cubes together, one face from each cube becomes hidden. This means that only 5 faces will be visible on the connected pair of cubes.
If we continue to connect more cubes in a row, we need to consider the connections between each pair. For every pair of connected cubes, one face from each cube will be hidden.
So, when Sonia connects the first cube, she will have 6 visible faces. When she adds the second cube and connects it to the first cube, she will have another 5 visible faces.
So far, we have 6 + 5 = 11 visible faces.
If she continues to add cubes and connect them in a row, each new cube will add 5 visible faces.
Therefore, with 5 cubes in a row, the number of visible faces will be:
11 + (5 * 3) = 11 + 15 = 26 visible faces.