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A triply ionized beryllium atom (Be3+) has only one electron in orbit about the nucleus. What is the radius of the ion when it is in the n = 9 excited state?

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  1. The radii = 5.29x10^-11*n^2

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    bobpursley
  2. So i did (5.29e-11)(81)= 4.2849e-9. But it still says that is incorrect...

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  3. are you certain n is supposed to be 9? That is pretty far out, I would expect in Be+3 an n=3 radii.

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    bobpursley
  4. That is what the question says n is

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  5. For hydrogen-like ion
    r(n) = 0.529•10^-10•n^2/Z ,
    where n is the NUMBER of exited state,
    and Z is the number of the element in the Periodic Table
    (for Be Z =4)
    =0.529•10^-10•81/4 = 1.071•10^-9 m

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