# physics

A bubble located 0.200m beneath the surface of a glass of beer rises to the top.the air pressure at the top of the glass is 1.01(10^5)pa.assume that the density of beer is the same as that of fresh water at 4 degrees celcius.if the temperature and number of moles of CO2 remain constant as the bubble rises,calculate the ratio of its volume at the top to that at the bottom

1. 0
2. 4
1. you have a pressure difference of 20cm of beer.

P1V1=P2V2

P1=P2+ beer heightpressure

solve for V2/V1

posted by bobpursley

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