two resistors are connected in parallel. Their resistances are 6 ohms and 10 ohms. What is the resistance, (R), of the combination?
R=-----ohms?
you just posted one like this
1/R = 1/6 + 1/10
now clear the fractions and solve for R
1/R = (10+6)/(10*6) = 4/15
R = 15/4 = 3.75
To find the total resistance of two resistors connected in parallel, you can use the formula:
1/R = 1/R1 + 1/R2
where R1 and R2 are the resistances of the individual resistors.
In this case, the resistances are given as 6 ohms (R1) and 10 ohms (R2).
So, substituting the given values into the formula:
1/R = 1/6 + 1/10
Now, let's simplify:
1/R = (10 + 6)/(6 * 10)
1/R = 16/60
To find R, we need to take the reciprocal of both sides of the equation:
R = 60/16
Now, simplifying this fraction:
R = 3.75 ohms
Therefore, the resistance (R) of the combination of the two resistors connected in parallel is 3.75 ohms.