if a=6 and b=-4, solve...(4a+4b) (4a-4b)
If I remember correctly,
a and b are variables. So you will substitute the value of a (which is 6) and the value for b (which is -4) into the problems.
Before you do that, remeber that 4a is actually 4 x a or, once you change the variable a to 6, 4 x 6 or 24. The same with 4b. 4b = 4 x b =4 x -4 = -16.
Do that for the numbers inside each parenthesis. Then perform the mathematical operation inside parenthesis. For the first parenthesis, the answer would be 24 + -16 which actually is 24-16 or 8. Repeat for the second parenthesis. Then multiply the sum in the first parenthesis by the difference in the second parenthesis.
Remember that when you multiply two negative numbers, the answer is positive. When you multiply a positive and negative number, the answer is negative.
(4a+4b) (4a-4b)
=4(a+b)4(a-b) , see the difference of squares?
= 16(a^2 - b^2)
= 16(36-16)
= 16(20)= 320
i need help w/ math and parentheses here is the question: 5=3+4-2/1 and i have to add parentheses.
To solve the expression (4a+4b)(4a-4b) given that a=6 and b=-4, we need to substitute these values into the expression and perform the computations.
Step 1: Substitute the values of a and b into the expression.
(4(6) + 4(-4))(4(6) - 4(-4))
Step 2: Perform the arithmetic operations within each set of parentheses.
(24 + (-16))(24 - (-16))
Step 3: Simplify the additions and subtractions inside the parentheses.
(8)(40)
Step 4: Multiply the two values inside the parentheses.
320
Therefore, the solution to the expression (4a+4b)(4a-4b) when a=6 and b=-4 is 320.