Math

Find y^1 for the relation 2 sin (x^2y)-5x^3=3y^2.
Please explain so I can work similar problems.

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asked by Mary
  1. Why do you write y^1? Is that a typo for y^-1, or y inverse?

    If so, forget it. You can't solve that equation explicitly for x or y.

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    posted by Steve

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