maths-probability

The diagram shows a spinner with six numbered sections.(where it has number 2 twice, # 1 triple & # 6 once )
Some of the sections are shaded.
Each time the spinner is spun it stops on one of the six sections.
It is equally likely that it stops on any one of the sections.
(a)The spinner is now spun twice. find the probability that the total of the 2 numbers is
(i)20 (ii) 11

(b)The spinner is now spun until it stops on a section numbered 2.
The probability that this happens on the nth spin is
16/243.
Find the value of n.
kindly show the steps

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asked by pooja
  1. Since all you can get is 1, 2 or 6
    there is no way to get a total of 20 or 11 with only 2 spins.
    looks like either a typo or a flaw in the question.

    2nd part.
    Spin until you get a 2 ....

    getting a 2 on
    1 spin = (1/3)
    2 spins = (2/3)(1/3) = 2^1 / 3^2
    3 spins = (2/3)^2 (1/3) = 2^2 / 3^3
    4 spins = (2/3)^3 (1/3) = 2^3 / 3^4
    ...
    n spins = 2^(n-1) / 3^n

    so 2^(n-1) / 3^n = 16/243
    2^(n-1) / 3^n = 2^4 / 3^5

    n = 5

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    posted by Reiny
  2. ard so i have a question. so im always on this web site looking for answers yes i do "cheat" if thats what you wanna call it. but half the time im confused, wth is the point in this website? is it to help you or is it for answers cuz i stay getting 100s on my tests from answers on here. i do do my work i just check the answers on here and if ion know a answer best believe this is my first stop but. like what is the point in the website.??? and if you got the answers for Lesson 3 Sample Spaces Unit 6 quick check post the answers cuz i need help. Thankkkss

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    posted by K. Baby

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