A car (mass=1100kg) is traveling at 32m/s when it collides head on with a sport utility vehicle (mass=2500kg) traveling in the opposite direction. In the collision, the two vehicles come to a halt. at what speed was the sport utility vehicle traveling.

m1*V1 = m2*V2.

1100*32 = 2500*V2.
V2 = (1100*32) / 2500 = 14.08 m/s.

Well, it sounds like these two vehicles had quite the "meet and greet" moment! To find out the speed of the sport utility vehicle, we can use the law of conservation of momentum. Since momentum is conserved, we can say that the momentum before the collision is equal to the momentum after the collision.

Now, the momentum of an object is given by its mass multiplied by its velocity. Let's call the velocity of the sport utility vehicle "V." The initial momentum of the car is (1100 kg) * (32 m/s), and the initial momentum of the sport utility vehicle is (2500 kg) * (-V) since it was traveling in the opposite direction.

Now, since the two vehicles come to a halt, the final momentum for both vehicles is 0. Therefore, we can set up the equation:

(1100 kg) * (32 m/s) + (2500 kg) * (-V) = 0

Now, let's solve for V. Don't worry, I won't leave you hanging!

Calculating... calculating... (imagine some funny circus music playing)...

After some calculations, we find that the speed of the sport utility vehicle was approximately 14.08 m/s. So, it was probably cruising with some moderate speed there!

Remember, always drive safely, because collisions can turn your car into a circus act!

To find the speed of the sport utility vehicle, we can use the principle of conservation of momentum. In an isolated system, the total momentum before the collision is equal to the total momentum after the collision.

Let's assume the initial velocity of the car is vCar = 32 m/s, and the initial velocity of the sport utility vehicle is vSUV (which we need to find).

The momentum of an object is given by the product of its mass and velocity:
Momentum = mass × velocity

Before the collision:
Momentum of the car = mass of the car × velocity of the car
Momentum of the SUV = mass of the SUV × velocity of the SUV

After the collision, both vehicles come to a halt, so the final velocity of both vehicles is 0 m/s. Using the principle of conservation of momentum, we can write:

Momentum before collision = Momentum after collision

(mass of the car × velocity of the car) + (mass of the SUV × velocity of the SUV) = 0

Plugging in the given values:

(1100 kg × 32 m/s) + (2500 kg × vSUV) = 0

Simplifying the equation, we get:

35200 kg·m/s + 2500 kg × vSUV = 0

2500 kg × vSUV = -35200 kg·m/s

Dividing both sides by 2500 kg, we find:

vSUV = -35200 kg·m/s ÷ 2500 kg

vSUV = -14.08 m/s

Since speed is a scalar quantity, the negative sign indicates that the sport utility vehicle was traveling in the opposite direction to the car.

Therefore, the sport utility vehicle was traveling at a speed of approximately 14.08 m/s in the opposite direction.

To find the speed at which the sport utility vehicle (SUV) was traveling, we need to apply the law of conservation of momentum. The law states that the total momentum before a collision is equal to the total momentum after the collision. Mathematically, this can be expressed as:

(mass of the car × velocity of the car) + (mass of the SUV × velocity of the SUV) = 0

Let's denote the velocity of the SUV by v.

The mass of the car (m1) is given as 1100 kg, and its velocity (v1) is given as 32 m/s. The mass of the SUV (m2) is given as 2500 kg, and we need to find the velocity (v2).

Using the conservation of momentum equation, we can write:

(1100 kg × 32 m/s) + (2500 kg × v) = 0

Solving for v:

35200 kg·m/s + 2500 kg·v = 0

2500 kg·v = -35200 kg·m/s

v = (-35200 kg·m/s) / 2500 kg

v = -14.08 m/s

The negative sign indicates that the SUV was traveling in the opposite direction. To find the magnitude of the velocity, we take the absolute value:

|v| = |-14.08 m/s| = 14.08 m/s

Therefore, the speed at which the sport utility vehicle was traveling before the collision was approximately 14.08 m/s.