How many mL of 5.5 M KOH are needed to prepare 300 mL of 1.2 M NaOH?
You can't prepare 1.2 M NaOH with KOH, not matter how much you use.
65.5
To determine how many mL of 5.5 M KOH are needed to prepare 300 mL of 1.2 M NaOH, you can use the concept of molarity (M) and the equation:
M1V1 = M2V2
where:
M1 = molarity of the stock solution (KOH)
V1 = volume of the stock solution (KOH) to be used
M2 = molarity of the desired solution (NaOH)
V2 = volume of the desired solution (NaOH)
In this case, we know:
M1 = 5.5 M (molarity of KOH)
V1 = unknown (volume of KOH to be used)
M2 = 1.2 M (molarity of NaOH)
V2 = 300 mL (volume of NaOH desired)
By substituting known values into the equation, we can solve for V1:
(5.5 M) V1 = (1.2 M) (300 mL)
V1 = (1.2 M) (300 mL) / 5.5 M
Calculating it gives:
V1 = 65.45 mL
Therefore, you would need to measure out approximately 65.45 mL of the 5.5 M KOH solution to prepare 300 mL of the 1.2 M NaOH solution.