E cell= E naught cell- (0.02570 V/n) lnQ
where Q=1/([H+]^4[SO42-])
calculate E cell at 25 c if [H2SO4]=10.0M
help?
To calculate E cell at 25°C using the equation E cell = E naught cell - (0.02570 V/n) lnQ, where Q = 1 / ([H+]^4[SO42-]), and [H2SO4] = 10.0 M, you need to follow these steps:
Step 1: Find E naught cell value
You need the standard cell potential, E naught cell, for the reaction. This value can be found in tables or given to you. Let's assume it's given as 0.95 V.
Step 2: Calculate the concentration of H+ and SO42-
Since [H2SO4] = 10.0 M, and it is a strong acid that fully dissociates in water, the concentration of H+ and SO42- will be the same. Therefore, [H+] = [SO42-] = 10.0 M.
Step 3: Calculate Q
Substitute the values into the equation Q = 1 / ([H+]^4[SO42-]):
Q = 1 / (10.0^4 * 10.0^4) = 1 / 10^8 = 1 * 10^-8
Step 4: Calculate E cell
Substitute the values into the equation E cell = E naught cell - (0.02570 V/n) lnQ:
E cell = 0.95 V - (0.02570 V/4) ln(1 * 10^-8)
Step 5: Calculate the natural logarithm of Q
ln(1 * 10^-8) ≈ -18.4207 (using a calculator)
Step 6: Substitute the values into the equation E cell
E cell = 0.95 V - (0.02570 V/4) * (-18.4207)
Step 7: Calculate E cell
E cell = 0.95 V + 0.0361 V ≈ 0.9861 V
Therefore, at 25°C with [H2SO4] = 10.0 M, the cell potential, E cell, is approximately 0.9861 V.