I have to calculate the concentration of I2 produced (# of moles of I2 produced / L) based on the stoichiometric ratio in the following equation.
2S2O3^2- + I2 -> 2I^- + S4O6^2-
Would the # produced be 2 for I2. I am not sure what to use for L?
If you know the number of moles of S2O3^2- then the number of mols I2 will be 1/2 that. I suspect you have M and L of S2O3^- and M x L = moles S2O3^2-.
All I have is the concentration of S2O3^-2 which is 3.33e^-3M. How would I find moles? For the experiment we used 2.50mL of Na2S2O3. Do I use this to find moles?
moles = M x L
Would it be over the total liter of solution from the flask?
To calculate the concentration of I2 produced, you need to know the number of moles of I2 produced and the volume of the solution in which the reaction takes place.
In the given equation, the stoichiometric ratio between S2O3^2- and I2 is 2:1, which means that for every 2 moles of S2O3^2- consumed, 1 mole of I2 is produced.
If you have the number of moles of S2O3^2- consumed, you can use this stoichiometric ratio to determine the number of moles of I2 produced.
To calculate the concentration, you also need the volume of the solution in which the reaction occurs. This volume is typically expressed in liters (L).
So, to calculate the concentration of I2 produced, you would divide the number of moles of I2 produced by the volume of the solution in liters.
In your case, you mentioned that the number of moles of I2 produced is 2. However, this value should be determined based on the actual quantity of S2O3^2- consumed. Without that information, it is not possible to accurately determine the number of moles of I2 produced.
To calculate the concentration of I2, you need to know the volume of the solution in which the reaction takes place, usually measured in liters (L). Once you have both the number of moles of I2 produced and the volume of the solution, you can divide the number of moles by the volume to find the concentration in moles per liter (mol/L).