(x+1)(x+3)=
FOIL
f: x^2
O: 3x
I: x
L: 3
add them
(x + 1)(x + 3)
= x^2 + 3x + x + 3
= x^2 + 4x + 3
To solve the expression (x+1)(x+3), we can use the distributive property. The distributive property states that when we multiply a sum by another number, we can individually multiply each term in the sum by that number and then add the products together.
Let's apply the distributive property to the expression (x+1)(x+3):
(x+1)(x+3) = x(x+3) + 1(x+3)
Now, we can simplify each term:
x(x+3) = x^2 + 3x
1(x+3) = x + 3
Finally, we add the simplified terms together:
(x+1)(x+3) = x^2 + 3x + x + 3
Combining like terms, we get the final result:
(x+1)(x+3) = x^2 + 4x + 3
Therefore, the expression (x+1)(x+3) simplifies to x^2 + 4x + 3.