How many liters of 0.101 m NaCl contains
1.70 mol of this salt? Assume this solvent is H2O.
Answer in units of L
I do not understand what i am looking for or how to solve for it. Steps would be appreciated.
I'm assume that is 0.101m and not 0.101M.
I'm not completely sure I understand it either; I don't think this problem can be worked without the density of the solution. Since it is a relatively weak solution, however, we can get close.
0.101m = 0.101 mol/kg solvent which is approximately = 0.101 mol/1000 g soln.
Then 1L x (1.7/0.101) = ? L needed.
(Note: if you meant 0.101M, then the last line is not an approximation and you don't need density.)
To determine the number of liters of a 0.101 M NaCl solution that contains 1.70 mol of NaCl, we can use the relationship between moles, concentration, and volume.
Here are the steps to solve this problem:
Step 1: Define the known quantities:
- The concentration of the NaCl solution is 0.101 M.
- The number of moles of NaCl is 1.70 mol.
Step 2: Use the equation:
Concentration (M) = Moles (mol) / Volume (L)
To rearrange the equation to solve for volume (V), we can divide both sides of the equation by concentration (M):
Volume (V) = Moles (mol) / Concentration (M)
Step 3: Substitute the known values into the equation:
V = 1.70 mol / 0.101 M
Step 4: Perform the calculation:
V = 16.83 L
Step 5: Round the answer to the appropriate number of significant figures:
The answer, rounded to three significant figures, is 16.8 L.
Therefore, 1.70 mol of NaCl dissolved in 16.8 liters of a 0.101 M NaCl solution when the solvent is H2O.